30:
\(\Leftrightarrow\left(\dfrac{4x-28}{1047}-1\right)+\left(\dfrac{4x-20}{1055}-1\right)+\left(\dfrac{4x-12}{1063}-1\right)+\left(\dfrac{4x-4}{1071}-1\right)+\left(\dfrac{4x+4}{1079}-1\right)=\left(\dfrac{4x-1079}{-4}-1\right)+\left(\dfrac{4x-1071}{4}-1\right)\)\(+\left(\dfrac{4x-1063}{12}-1\right)+\left(\dfrac{4x-1055}{20}-1\right)+\left(\dfrac{4x-1047}{28}-1\right)\)
=>4x-1075=0
=>x=1075/4

Mn giúp em với ạ. thanks
Mọi người ơi giúp em với ạ, em đang cần gấp, thanks mn


