\(C=25.\left(\dfrac{-1}{125}\right)+\dfrac{1}{5}-2.\dfrac{1}{4}-1\\ =-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{2}{4}-1=0-\dfrac{1}{2}-1=-\dfrac{1}{2}-1=\dfrac{-1-2}{2}=-\dfrac{3}{2}\)
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