\(\left\{{}\begin{matrix}x+y=500\\\dfrac{8}{10}x+\dfrac{9}{10}y=420\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=500-y\\\dfrac{8}{10}\left(500-y\right)+\dfrac{9}{10}y=420\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=500-y\\400+\dfrac{y}{10}=420\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=500-y=300\\y=200\end{matrix}\right.\)
Vậy (x,y)=(300,200)
hpt <=> \(\left\{{}\begin{matrix}\dfrac{8}{10}x+\dfrac{8}{10}y=400\\\dfrac{8}{10}x+\dfrac{9}{10}y=420\end{matrix}\right.\)
<=>\(\left\{{}\begin{matrix}x+y=500\\\dfrac{1}{10}y=20\end{matrix}\right.\)
<=> \(\left\{{}\begin{matrix}x+y=500\\y=200\end{matrix}\right.\)
<=>\(\left\{{}\begin{matrix}x=300\\y=200\end{matrix}\right.\)