\(\left(3x+8\right)\left(4x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}3x+8=0\\4x-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}3x=-8\\4x=1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{8}{3}\\x=\dfrac{1}{4}\end{matrix}\right.\)
\(\left(3x+8\right)\left(4x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+8=0\\4x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}3x=-8\\4x=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{8}{3}\\x=\dfrac{1}{4}\end{matrix}\right.\)
\(\left(3x+8\right)\left(4x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+8=0\\4x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=-8\\4x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-8}{3}\\x=\dfrac{1}{4}\end{matrix}\right.\)
\(\text{Vậy phương trình có tập nghiệm là }S=\left\{\dfrac{-8}{3};\dfrac{1}{4}\right\}\)
