Question

giải pt sau: \(\dfrac{1}{x-5}\)-\(\dfrac{4}{\left(x-5\right)\left(x-1\right)}\)=\(\dfrac{5}{x-1}\)

Answer 1

\(\Leftrightarrow x-1-4=5\left(x-5\right)\)

=>x-5=5(x-5)

=>x-5-5x+25=0

=>-4x+20=0

hay x=5(loại)

Answer 2

`1/[x-5]-4/[(x-5)(x-1)]=5/[x-1]`       `ĐK: x \ne 5,x \ne 1`

`<=>[x-1-4]/[(x-5)(x-1)]=[5(x-5)]/[(x-5)(x-1)]`

   `=>x-5=5x-25`

`<=>4x=20`

`<=>x=5` (ko t/m)

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