Question

giải phương trình 

3x(x-1)+2(1-x)=0

Answer 1

`3x(x-1)+2(1-x)=0`

`<=>3x(x-1)-2(x-1)=0`

`<=>(x-1)(3x-2)=0`

\(< =>\left[{}\begin{matrix}x-1=0\\3x+2=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=1\\x=-\dfrac{2}{3}\end{matrix}\right.\)

Answer 2

`3x(x-1)+2(1-x)=0`

`<=> 3x(x-1)-2(x-1)=0`

`<=>(x-1)(3x-2)=0`

`<=>x-1=0` hoặc `3x-2=0`

`<=> x=1` hoặc `3x=2`

`<=>x=1` hoặc `x=2/3`

Answer 3

\(3x\left(x-1\right)+2\left(1-x\right)=0\)

\(\Leftrightarrow3x\left(x-1\right)-2\left(x-1\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(3x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-1=0\\3x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{2}{3}\end{matrix}\right.\)