Question

giải giúp mik bài này ạ

Answer 1

\(x^4-4x^2+x^2-4x=0\)

\(\Leftrightarrow x^2\left(x^2-4\right)+x\left(x-4\right)=0\)

\(\Leftrightarrow x\left(x^3-4x+x-4\right)=0\)

\(\Leftrightarrow x\left(x^3-3x-4\right)=0\)

hay x=0

Answer 2

\(\Leftrightarrow x\left(x^3-3x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x^3-3x-4=0\end{matrix}\right.\\ \Leftrightarrow x=0\)

Answer 3

-2x(x-2)=0

TH1:-2x=0 =>x=0

TH2:x-2=0 =>x=2