Áp dụng BĐT Cô-si:
\(3\left(a^2+4\right)\ge3.4a=12a\)
\(b^4+b^4+b^4+81\ge4\sqrt[4]{81b^{12}}=12b^3\)
Cộng vế:
\(3\left(a^2+b^4\right)+93\ge12\left(a+b^3\right)=384\)
\(\Rightarrow a^2+b^4\ge85\)
\(\Rightarrow P\ge85-19=66\)
\(P_{min}=66\) khi \(\left(a;b\right)=\left(2;3\right)\)