Lời giải:
$\frac{x}{1}-\frac{115-x}{2}=25$
$x-\frac{115-x}{2}=25$
$\frac{115-x}{2}=x-25$
$115-x=2(x-25)=2x-50$
$115+50=2x+x$
$165=3x$
$x=165:3=55$
giai phuong trinh
(x^2 + 1)^2 + 3x(x^2 + 1) + 2x^2 = 0
(x^2 - 9)^2 = 12x + 1
giai chi tiet gium nha
Giai pt
a/\(\dfrac{x+2}{x-2}-\dfrac{2}{x^2-2x}=\dfrac{1}{x}\)
b/\(\dfrac{1}{x-1}-\dfrac{3x^2}{x^3-1}=\dfrac{2x}{x^2+x+1}\)
4/x+2 + (-3)/x-2 + 12/x^2-4 giai chi tiet ho mk !
Giai phương trình\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}+\dfrac{x^2+3x-2}{1-x^2}=0\)
GPT: x5-x4+3x3+3x2-x+1=0
giai chi tiet gium
trung binh cong cac gia tri x thoa mam
4(x-1)2=x2
giai chi tiet nha
Giai phương trình :
a)\(\dfrac{2x-1}{3}-x=\dfrac{x+3}{4}+2\)
b)\(x^2-4+\left(x-9\right)\left(x-2\right)=0\)
c)\(\dfrac{x-1}{x-3}-\dfrac{1}{x+3}=\dfrac{3x+3}{x^2-9}\)
Giai cac bpt sau
a,\(\dfrac{4x-2}{3}-x+3\le\dfrac{1-5x}{4}\)
b,\(\dfrac{x+4}{5}-x-5\ge\dfrac{x+3}{3}-\dfrac{x-2}{2}\)
(\(\dfrac{x^2-5x}{x^2-25}\)-1):(\(\dfrac{25-x^2}{x^2+2x-15}\)-\(\dfrac{x+3}{x+5}\)-\(\dfrac{x-3}{x-5}\))
Giai các bpt sau
a,\(\dfrac{5x^2-3}{5}+\dfrac{3x-1}{4}< \dfrac{x\left(2x+3\right)}{2}-5\)
b,\(\dfrac{5x-2}{-3}\)\(-\dfrac{2x^2-x}{-2}>\dfrac{x\left(1-3x\right)}{-3}-\dfrac{5x}{-4}\)
