c) \(\dfrac{x+5}{x^2-5x}-\dfrac{x-5}{2x^2+10x}=\dfrac{x+25}{2x^2-50}\)
\(\Leftrightarrow\dfrac{x+5}{x\left(x-5\right)}-\dfrac{x-5}{2x\left(x+5\right)}=\dfrac{x+25}{2\left(x^2-25\right)}\)
\(\Leftrightarrow\dfrac{2\left(x+5\right)\left(x-5\right)}{2x\left(x+5\right)\left(x-5\right)}-\dfrac{\left(x-5\right)^2}{2x\left(x+5\right)\left(x-5\right)}=\dfrac{\left(x+25\right)x}{2x\left(x+5\right)\left(x-5\right)}\)
\(\Leftrightarrow2\left(x^2-25\right)-\left(x^2-10x+25\right)=x^2+25x\)
\(\Leftrightarrow2x^2-50-x^2+10x-25=x^2+25x\)
\(\Leftrightarrow2x^2-x^2-x^2+10x-25x=50+25\)
\(\Leftrightarrow-15x=75\)
\(\Leftrightarrow x=\dfrac{75}{-15}\)
\(\Leftrightarrow x=-5\)
bpt là dấu lớn bé mà trên là dấu `=` đề nó phải là giải pt chứ ạ?
