ĐKXĐ: \(\left\{{}\begin{matrix}2x-1>0\\27-4x>0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>\dfrac{1}{2}\\x< \dfrac{27}{4}\end{matrix}\right.\)
=>0,5<x<6,75
\(log_3\left(2x-1\right)+1< log_3\left(27-4x\right)\)
=>\(log_3\left(2x-1\right)+log_33< log_3\left(27-4x\right)\)
=>\(log_3\left(6x-3\right)< log_3\left(27-4x\right)\)
=>6x-3<27-4x
=>10x<30
=>x<3
mà 0,5<x<6,75
nên 0,5<x<3