\(4x^3=4x\)
=>\(x^3=x\)
=>\(x^3-x=0\)
=>\(x\cdot\left(x^2-1\right)=0\)
=>\(x\left(x-1\right)\left(x+1\right)=0\)
=>\(\left[{}\begin{matrix}x=0\\x-1=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=1\\x=-1\end{matrix}\right.\)
4x³ = 4x
4x³ - 4x = 0
4x(x² - 1) = 0
4x = 0 hoặc x² - 1 = 0
*) 4x = 0
x = 0
*) x² - 1 = 0
x² = 1
x = 1 hoặc x = -1
Vậy x = -1; x = 0; x = 1