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Question

f) -2x^2 + 7xy - 3y^2g) 2a^2 + 5ab - 3b^2h) 6x^4 - 11x^2 + 3

HT.Phong (9A5) · Accepted Answer

$f.-2x^2+7xy-3y^2\
=\left(-2x^2+xy\right)+\left(6xy-3y^2\right)\
=x\left(-2x+y\right)+3y\left(2x-y\right)\
=-x\left(2x-y\right)+3y\left(2x-y\right)\
=\left(2x-y\right)\left(-x+3y\right)\
g.2a^2+5ab-3b^2\
=\left(2a^2+6ab\right)-\left(ab+3b^2\right)\
=2a\left(a+3b\right)-b\left(a+3b\right)\
=\left(2a-b\right)\left(a+3b\right)\
h.6x^4-11x^2+3\
=\left(6x^4-9x^2\right)+\left(-2x^2+3\right)\
=3x^2\left(2x^2-3\right)-\left(2x^2-3\right)\
=\left(2x^2-3\right)\left(3x^2-1\right)$Câu trả lời: $f.-2x^2+7xy-3y^2\
=\left(-2x^2+xy\right)+\left(6xy-3y^2\right)\
=x\left(-2x+y\right)+3y\left(2x-y\right)\
=-x\left(2x-y\right)+3y\left(2x-y\right)\
=\left(2x-y\right)\left(-x+3y\right)\
g.2a^2+5ab-3b^2\
=\left(2a^2+6ab\right)-\left(ab+3b^2\right)\
=2a\left(a+3b\right)-b\left(a+3b\right)\
=\left(2a-b\right)\left(a+3b\right)\
h.6x^4-11x^2+3\
=\left(6x^4-9x^2\right)+\left(-2x^2+3\right)\
=3x^2\left(2x^2-3\right)-\left(2x^2-3\right)\
=\left(2x^2-3\right)\left(3x^2-1\right)$

Nguyễn Việt Lâm · Answer

Đề yêu cầu gì em nhỉ?Câu trả lời: Đề yêu cầu gì em nhỉ?

a) x² – 4 – (x + 2)²	b) (x + 2)(x – 2) – (x – 3)(x + 1)
c) (x – 2)(x + 2) – (x – 2)(x + 5)	d) (6x + 1)² + (6x – 1)² – 2(6x + 1)(6x – 1)
e) 7a(3a – 5) + (2a -3)(4a + 1) – (6a – 2)²	g) (5y – 3)(5y + 3) – (5y – 4)²
h) (3x + 1)³ – (1 – 2x)³	i) (2x + 1)² + 2(4x² – 1) + (2x – 1)²

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