Ta có: \(n_{O_2}=\dfrac{2,479}{24,79}=0,1\left(mol\right)\)
PT: \(4P+5O_2\underrightarrow{t^o}2P_2O_5\)
a, \(n_P=\dfrac{4}{5}n_{O_2}=0,08\left(mol\right)\Rightarrow m_P=0,08.31=2,48\left(g\right)\)
b, \(n_{P_2O_5}=\dfrac{2}{5}n_{O_2}=0,04\left(mol\right)\Rightarrow m_{P_2O_5}=0,04.142=5,68\left(g\right)\)
\(n_{O_2}=\dfrac{2.479}{22.4}=0.1\left(mol\right)\)\(n_{O_2}=\dfrac{2.479}{24.79}=0.1\left(mol\right)\)
\(4P+5O_2\underrightarrow{^{^{t^o}}}2P_2O_5\)
\(0.08....0.1......0.04\)
\(a.m_P=0.08\cdot31=2.48\left(g\right)\)
\(b.m_{P_2O_5}=0.04\cdot142=5.68\left(g\right)\)
