\(n_C=\dfrac{2,2}{44}=0,05\left(mol\right)\\ n_H=2.\dfrac{1,35}{18}=0,15\left(mol\right)\\ n_O=\dfrac{1,15-0,05.12-0,15}{16}=0,025\left(mol\right)\)
\(CTPT:C_xH_yO_z\\ \Rightarrow x:y:z=0,05:0,15:0,025=2:6:1\\ \Rightarrow\left(C_2H_6O\right)_n=1,4375.32=46\left(\dfrac{g}{mol}\right)\\ \Rightarrow n=1\\ CTPT:C_2H_6O\)