Question

\(\dfrac{x+2}{4}-x+3-\dfrac{1-x}{8}=0\)

Answer 1

\(\dfrac{x+2}{4}-x+3-\dfrac{1-x}{8}=0\)

\(\dfrac{\left(x+2\right).2}{4.2}-\dfrac{\left(x-3\right).8}{1.8}-\dfrac{1-x}{8}=0\)

\(\Rightarrow2x+4-8x+24-1+x=0\)

\(\Leftrightarrow2x-8x+x=-4-24+1\)

\(\Leftrightarrow-5x=-27\)

\(\Leftrightarrow x=\dfrac{27}{5}\)

Answer 2

=>2(x+2)+8(-x+3)-1+x=0

=>2x+4-8x+24+x-1=0

=>-5x+27=0

=>x=27/5