Question

\(\dfrac{\sqrt{33}-\sqrt{6}}{\sqrt{11}-\sqrt{2}}-\sqrt{12+6\sqrt{3}}\)

Answer 1

\(=\sqrt{3}-3-\sqrt{3}=-3\)

Answer 2

Lần sau bạn lưu ý viết đầy đủ yêu cầu đề bài.

Lời giải:
\(\frac{\sqrt{33}-\sqrt{6}}{\sqrt{11}-\sqrt{2}}-\sqrt{12+6\sqrt{3}}=\frac{\sqrt{3}(\sqrt{11}-\sqrt{2})}{\sqrt{11}-\sqrt{2}}-\sqrt{(3+\sqrt{3})^2}\)

\(=\sqrt{3}-|3+\sqrt{3}|=\sqrt{3}-(3+\sqrt{3})=-3\)