Question

\(\dfrac{7}{2}+\left|x+\dfrac{1}{2}\right|=\dfrac{9}{2}\)

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Answer 1

`7/2+|x+1/2|=9/2`

`|x+1/2|=9/2-7/2=1`

`@TH1:x+1/2=1=>x=1-1/2=1/2`

`@TH2:x+1/2=-1=>x=-1-1/2=-3/2`

Vậy `x in {1/2;-3/2}`

Answer 2

Answer 3

`7/2 + | x + 1/2| = 9/2`

`|x + 1/2| = 9/2 - 7/2`

`|x + 1/2| = 2/2`

`|x + 1/2| = 1`

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=-1\\x+\dfrac{1}{2}=1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-1-\dfrac{1}{2}\\x=1-\dfrac{1}{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

Vậy....

`#BaoL i n h`