Question

\(^{\dfrac{7^{10}+7^4}{7^8+7^6}}\)

Answer 1

Lời giải:
\(\frac{7^{10}+7^4}{7^8+7^6}=\frac{7^4(7^6+1)}{7^6(7^2+1)}=\frac{7^6+1}{7^2(7^2+1)}=\frac{(7^2+1)(7^4-7^2+1)}{7^2(7^2+1)}\)

$=\frac{7^4-7^2+1}{7^2}=\frac{2353}{49}$

Answer 2

`= (7^4(7^6+1))/(7^6(7^2+1))`

`= (7^6+1)/(7^2(7^2+1))`

`= (7^4-7x^2+1)/7^2=2353/49`.

Answer 3

710+7478+76=74(76+1)76(72+1)=76+172(72+1)=(72+1)(74−72+1)72(72+1)710+7478+76=74(76+1)76(72+1)=76+172(72+1)=(72+1)(74−72+1)72(72+1)

$=\frac{{}^{}-{}^{}+1}{{}^{}}=\frac{2353}{49}$