=>5/9:x=11/5-4/7=57/35
=>x=5/9:57/35=175/513
\(\dfrac{4}{7}+\dfrac{5}{9}:x=\dfrac{11}{5}\)
\(\dfrac{5}{9}:x=\) \(\dfrac{11}{5}-\dfrac{4}{7}\)
\(\dfrac{5}{9}:x=\dfrac{57}{35}\)
\(x=\dfrac{5}{9}:\dfrac{57}{35}\)
\(x=\dfrac{175}{513}\)
=>5/9:x=11/5-4/7=57/35
=>x=5/9:57/35=175/513
\(\dfrac{4}{7}+\dfrac{5}{9}:x=\dfrac{11}{5}\)
\(\dfrac{5}{9}:x=\) \(\dfrac{11}{5}-\dfrac{4}{7}\)
\(\dfrac{5}{9}:x=\dfrac{57}{35}\)
\(x=\dfrac{5}{9}:\dfrac{57}{35}\)
\(x=\dfrac{175}{513}\)
a,\(\dfrac{1}{7}\text{x}\dfrac{2}{7}+\dfrac{1}{7}\text{x}\dfrac{5}{7}+\dfrac{6}{7}\) b,\(\dfrac{6}{11}\text{x}\dfrac{4}{9}+\dfrac{6}{11}\text{x}\dfrac{7}{9}-\dfrac{6}{11}\text{x}\dfrac{2}{9}\)
c, \(\dfrac{4}{25}\text{x}\dfrac{5}{8}\text{x}\dfrac{25}{4}\text{x}24\)
Tính giá trị biểu thức:
(\(\dfrac{6}{11}+\dfrac{5}{11}\)) x \(\dfrac{3}{7}\) \(\dfrac{3}{5}x\dfrac{7}{9}-\dfrac{3}{5}x\dfrac{2}{9}\) \(\left(\dfrac{6}{7}-\dfrac{4}{7}\right):\dfrac{2}{5}\)
1.Tính
\(a,5\text{x}\dfrac{7}{3}\) \(b,\dfrac{13}{4}:7\)
2.Tính
\(a,\dfrac{3}{7}+\dfrac{2}{5}+\dfrac{3}{4}\) \(b,\dfrac{9}{7}-\dfrac{5}{11}\text{x}\dfrac{11}{7}\) \(c,\dfrac{3}{5}\text{x}\dfrac{5}{7}\text{+}\dfrac{4}{7}\) \(d,\dfrac{7}{9}\text{x}\dfrac{2}{5}:\dfrac{3}{11}\) e,\(\dfrac{9}{7}+\dfrac{2}{3}-\dfrac{1}{4}\)
g,\(\dfrac{4}{9}:\dfrac{3}{5}\text{x}\dfrac{2}{11}\) h,\(\dfrac{7}{2}-\dfrac{3}{10}:\dfrac{2}{5}\)
Ôn tập lain kiến thức lớp bốn:)
\(\dfrac{1}{24}x\dfrac{72}{23}+\dfrac{1}{46}\). \(\dfrac{9}{11}+\dfrac{1}{12}:\dfrac{11}{24}\). \(\dfrac{4}{7}-\dfrac{1}{5}x\dfrac{5}{9}\)
Một mảnh đất hình thoi có tổng độ dai hai đường chéo là 180m . Đường chéo thứ nhất hơn đường chéo thứ hai là 24m. TÍNH DIỆN TÍCH MẢNH ĐẤT HÌNH THOI ĐÓ .
AI NHỚ KIẾN THỨC SSEN XUON DƯỚI NHÉ
Tìm x:
\(\dfrac{3}{5}\) : x = \(\dfrac{1}{3}+\dfrac{1}{2}\) x : \(\dfrac{7}{12}\) = 2 x - \(\dfrac{3}{2}\) = \(\dfrac{11}{4}-\dfrac{5}{4}\) x + \(\dfrac{5}{4}\) = \(\dfrac{3}{2}+\dfrac{7}{12}\)
a)\(\dfrac{7}{8}\)x\(\dfrac{3}{13}\)+\(\dfrac{4}{9}\)x\(\dfrac{4}{13}\)
b)\(\dfrac{6}{5}\)+\(\dfrac{7}{3}\)+\(\dfrac{8}{9}\)
c)23: \(\dfrac{5}{14}\)+\(\dfrac{6}{7}\)+\(\dfrac{4}{9}\)
d)\(4\dfrac{1}{4}\)+\(7\dfrac{3}{7}\)-\(2\dfrac{4}{17}\)
e)8-(9\(\dfrac{2}{11}\)+\(\dfrac{8}{33}\))
\(\dfrac{1}{3}+\dfrac{2}{3}=\)
\(\dfrac{4}{5}+\dfrac{5}{6}=\)
\(\dfrac{4}{5}-\dfrac{3}{5}=\)
\(\dfrac{9}{8}-\dfrac{4}{2}=\)
\(\dfrac{8}{5}x\dfrac{5}{8}=\)
\(\dfrac{6}{7}x\dfrac{4}{7}=\)
\(\dfrac{4}{5}:\dfrac{4}{5}=\)
\(\dfrac{5}{5}:\dfrac{5}{5}=\)
a,
3\(\dfrac{1}{3}\)+\(\dfrac{5}{6}\) 4\(\dfrac{5}{7}\)-2\(\dfrac{11}{21}\) 3\(\dfrac{1}{4}\)x\(\dfrac{2}{5}\) 4\(\dfrac{7}{8}\):\(\dfrac{1}{4}\)