Ta có: \(\dfrac{30}{x}-\dfrac{30}{x+3}=\dfrac{1}{2}\)
\(\Leftrightarrow60\left(x+3\right)-60x=x\left(x+3\right)\)
\(\Leftrightarrow x^2+3x-180=0\)
\(\Leftrightarrow x^2+15x-12x-180=0\)
\(\Leftrightarrow\left(x+15\right)\left(x-12\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-15\left(nhận\right)\\x=12\left(nhận\right)\end{matrix}\right.\)