Question

\(\dfrac{2}{x+1}\)-\(\dfrac{1}{x-2}\)=\(\dfrac{3x-11}{\left(x+1\right)\left(x-2\right)}\)

Answer 1

ĐKXĐ: \(x\ne-1;x\ne2\)

\(\dfrac{2}{x+1}-\dfrac{1}{x-2}=\dfrac{3x-11}{\left(x+1\right)\left(x-2\right)}\\ \Leftrightarrow\dfrac{2x-4-x-1}{\left(x+1\right)\left(x-2\right)}=\dfrac{3x-11}{\left(x+1\right)\left(x-2\right)}\\ \Rightarrow x-5=3x-11\\ \Leftrightarrow2x=6\\ \Leftrightarrow x=3\left(TM\right)\)

Vậy tập nghiệm của Pt là S={3}