\(\dfrac{2}{7}x=\dfrac{4}{15}+\dfrac{3}{5}\)
\(\dfrac{2}{7}x=\dfrac{13}{15}\)
\(x=\dfrac{13}{15}:\dfrac{2}{7}\)
\(x=\dfrac{13}{15}x\dfrac{7}{2}\)
\(x=\dfrac{91}{30}\)
\(\dfrac{2}{7}x-\dfrac{3}{5}=\dfrac{4}{15}\)
⇔ \(\dfrac{2}{7}x=\dfrac{4}{15}+\dfrac{3}{5}\)
⇔\(\dfrac{2}{7}x=\dfrac{13}{15}\)
⇔\(x=\dfrac{13}{15}:\dfrac{2}{7}\)
⇔\(x=\dfrac{91}{30}\)
\(\dfrac{2}{7}\)x-\(\dfrac{3}{5}\)=\(\dfrac{4}{15}\)
=> \(\dfrac{2}{7}\)x=\(\dfrac{13}{15}\)
=> x=\(\dfrac{91}{30}\)
Ta có: \(\dfrac{2}{7}x-\dfrac{3}{5}=\dfrac{4}{15}\)
\(\Leftrightarrow\dfrac{2}{7}x=\dfrac{4}{15}+\dfrac{3}{5}=\dfrac{4}{15}+\dfrac{9}{15}=\dfrac{13}{15}\)
hay \(x=\dfrac{13}{15}:\dfrac{2}{7}=\dfrac{91}{30}\)