Question

\(\dfrac{2}{3}\).\(\dfrac{1}{7}\)+\(\dfrac{2}{3}\).\(\dfrac{6}{7}\)_\(\dfrac{1}{3}\)

Answer 1

`2/3 . 1/7 + 2/3 . 6/7 - 1/3 `

`= 2/3 ( 1/7 + 6/7 ) - 1/3`

`= 2/3 . 1 - 1/3`

`= 2/3 - 1/3`

`=1/3`

Answer 2

\(\dfrac{2}{3}.\dfrac{1}{7}+\dfrac{2}{3}.\dfrac{6}{7}-\dfrac{1}{3}=\dfrac{2}{3}.\left(\dfrac{1}{7}+\dfrac{6}{7}\right)-\dfrac{1}{3}=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)

Answer 3

Tham khảo