\(\dfrac{1}{4}>\dfrac{1}{9};\dfrac{5}{8}< \dfrac{8}{5}\)
\(\dfrac{1}{4}>\dfrac{1}{9};\dfrac{5}{8}< \dfrac{8}{5}\)
A,\(\dfrac{8}{9}:\dfrac{4}{5}+\dfrac{3}{5}\)
B,\(\dfrac{5}{8}\) + \(\dfrac{1}{4}\)
C,\(\dfrac{7}{8}\) x \(\dfrac{4}{7}\) +\(\dfrac{5}{9}\)
D,\(\dfrac{9}{8}:\dfrac{4}{3}-\dfrac{4}{7}\)
\(\dfrac{2}{5}\) x \(\dfrac{3}{4}-\dfrac{1}{8}\) \(= \)
\(\dfrac{4}{3}+\dfrac{1}{3}-\dfrac{1}{5}=\)
\(\dfrac{9}{20}-\dfrac{3}{5}\) x \(\dfrac{1}{4}\)\(= \)
\(\dfrac{2}{8}+\dfrac{2}{3}:\dfrac{4}{5}\)\(=\)
\(\dfrac{3}{5}+\dfrac{1}{2}+\dfrac{8}{15}\)
\(\dfrac{6}{9}+\dfrac{14}{18}-\dfrac{5}{6}\)
\(\dfrac{9}{20}-\dfrac{3}{5}:\dfrac{4}{1}\)
\(\dfrac{1}{6}+\dfrac{2}{3}\) x \(\dfrac{8}{9}\)
\(x +\dfrac{5}{9} =\dfrac{4}{3}\)
\(x -\dfrac{4}{9}=\dfrac{2}{3}\)
\(\dfrac{5}{8}+x=\dfrac{8}{5} \)
\(\dfrac{5}{6}-x=\dfrac{1}{12}\)
so sánh hai phân số: a, \(\dfrac{5}{8}\) và \(\dfrac{7}{8}\) b, \(\dfrac{15}{25}\) và \(\dfrac{4}{5}\)
So sánh phân số : \(\dfrac{5}{6};\dfrac{9}{10};\dfrac{7}{8}\)
\(\dfrac{6}{8}...\dfrac{9}{5}\)
~so sánh~
so sánh :
\(\dfrac{8}{9} và
\dfrac{9}{3} ; \dfrac{8}{4} và
\dfrac{6}{3} \)
Điền dấu > ; < hoặc = vào chỗ chấm cho thích hợp:
a) \(\dfrac{3}{4}.....\dfrac{4}{5}\) b) \(\dfrac{11}{12}.....\dfrac{7}{8}\) c) \(\dfrac{5}{7}+\dfrac{3}{5}.....\dfrac{6}{7}:\dfrac{5}{8}\) d) \(\dfrac{9}{16}-\dfrac{5}{9}.....\dfrac{1}{16}x\dfrac{1}{9}\)