Ta có: \(-\dfrac{3}{7}-\dfrac{2}{21}+\left(2\dfrac{2}{3}-3\dfrac{1}{4}\right)=x-\dfrac{5}{3}\)
\(\Leftrightarrow x-\dfrac{5}{3}=-\dfrac{3}{7}-\dfrac{2}{21}+\dfrac{8}{3}-\dfrac{13}{4}\)
\(\Leftrightarrow x-\dfrac{5}{3}=-\dfrac{31}{28}\)
hay \(x=\dfrac{47}{84}\)
Vậy: \(x=\dfrac{47}{84}\)