Question

\(\dfrac{-3}{4}\) ( \(\dfrac{8}{9}\) - x ) + \(\dfrac{3}{5}\) = \(\dfrac{-2}{3}\) ( \(\dfrac{1}{2}\) )

Answer 1

\(-\dfrac{3}{4}\left(\dfrac{8}{9}-x\right)+\dfrac{3}{5}=-\dfrac{2}{3}.\dfrac{1}{2}=-\dfrac{1}{3}\\ \Leftrightarrow-\dfrac{3}{4}\left(\dfrac{8}{9}-x\right)=-\dfrac{1}{3}-\dfrac{3}{5}=-\dfrac{14}{15}\\ \Leftrightarrow\dfrac{8}{9}-x=\dfrac{56}{45}\\ \Leftrightarrow x=\dfrac{8}{9}-\dfrac{56}{45}=-\dfrac{16}{45}\)

Answer 2

Ta có : \(PT\Leftrightarrow-\dfrac{3}{4}\left(\dfrac{8}{9}-x\right)=-\dfrac{2}{3}.\dfrac{1}{2}-\dfrac{3}{5}=-\dfrac{14}{15}\)

\(\Rightarrow\dfrac{8}{9}-x=\dfrac{-\dfrac{14}{15}}{-\dfrac{3}{4}}=\dfrac{56}{45}\)

\(\Rightarrow x=\dfrac{8}{9}-\dfrac{56}{45}=-\dfrac{16}{45}\)

Vậy ...

Answer 3

\(\dfrac{-3}{4}\left(\dfrac{8}{9}-x\right)+\dfrac{3}{5}=\dfrac{-2}{3}.\dfrac{1}{2}\)

\(\Rightarrow\) \(\dfrac{-3}{4}\left(\dfrac{8}{9}-x\right)+\dfrac{3}{5}=-\dfrac{1}{3}\)

\(\Rightarrow\) \(\dfrac{-3}{4}\left(\dfrac{8}{9}-x\right)=-\dfrac{14}{15}\)

\(\Rightarrow\) \(\dfrac{8}{9}-x=\dfrac{56}{45}\)

\(\Rightarrow\) \(x=-\dfrac{16}{45}\)