Question

\(\dfrac{-3}{17}\cdot\dfrac{4}{7}+\dfrac{-3}{7}\cdot\dfrac{3}{17}+\dfrac{2}{-5}\)

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Answer 1

\(=\dfrac{3}{17}.\left(-\dfrac{4}{7}-\dfrac{3}{7}\right)-\dfrac{2}{5}\\ =\dfrac{3}{17}.\dfrac{-7}{7}-\dfrac{2}{5}\\ =\dfrac{-3}{17}-\dfrac{2}{5}\\ =\dfrac{-3.5-2.17}{85}=-\dfrac{49}{85}\)

Answer 2

\(=\dfrac{3}{17}\cdot\dfrac{-4}{7}+\dfrac{-3}{7}\cdot\dfrac{3}{17}+\dfrac{-2}{5}=\dfrac{3}{17}\cdot\left(-\dfrac{4}{7}+\dfrac{-3}{7}+\dfrac{-2}{5}\right)=\dfrac{3}{17}\cdot\dfrac{-7}{5}=-\dfrac{21}{85}\)