\(\dfrac{-2}{3}=\dfrac{18}{x}\)
\(\Leftrightarrow x=\dfrac{18.3}{-2}=-27\)
Vì \(\dfrac{-2}{3}=\dfrac{18}{x}\) nên -2x = 3.18
-2x = 54
x = 54:(-2)
x = -27
-2/3=18/x
Vậy -2*x=18*3
-2*x=54
x=54/-2
x=-27
\(\dfrac{-2}{3}=\dfrac{18}{x}\)
\(\Leftrightarrow x=\dfrac{18.3}{-2}=-27\)
Vì \(\dfrac{-2}{3}=\dfrac{18}{x}\) nên -2x = 3.18
-2x = 54
x = 54:(-2)
x = -27
-2/3=18/x
Vậy -2*x=18*3
-2*x=54
x=54/-2
x=-27
(11\(\dfrac{7}{18}\) - 9\(\dfrac{13}{18}\)): x - 1\(\dfrac{2}{33}\) : \(\dfrac{7}{11}\) = 1\(\dfrac{2}{3}\)
Tìm số nguyên x, y biết:
\(a,\dfrac{x}{5}=\dfrac{-18}{10}\) b, \(\dfrac{6}{x-1}=\)\(\dfrac{-3}{7}\) c, \(\dfrac{y-3}{12}\)=\(\dfrac{3}{y-3}\) d, \(\dfrac{x}{25}\)=\(\dfrac{-5}{x^2}\)
\(\dfrac{-3}{6}\) = \(\dfrac{x}{-2}\) = \(\dfrac{-18}{y}\) = \(\dfrac{-z}{24}\)
Tìm x,y,z
giúp mình với ạ
Bài 2: Tìm x, biết:
a) \(\left(x-\dfrac{5}{8}\right).\dfrac{5}{18}=-\dfrac{15}{36}\)
b) \(\left(x-\dfrac{1}{3}\right)=\dfrac{5}{6}\)
Tìm x, biết:
\(a,\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-1}{6}\)
\(b,\left(3x+2\right)\left(\dfrac{-2}{5}x-7\right)=0\)
\(c,\dfrac{x}{8}=\dfrac{9}{4}\)
\(d,\dfrac{x-3}{2}=\dfrac{18}{x-3}\)
\(e,4,5x-6,2x=6,12\)
\(h,11,4-\left(x-3,4\right)=-16,2\)
Tìm các số nguyên x,y biết:
a)\(\dfrac{6}{2x+1}=\dfrac{2}{7}\)
b) \(\dfrac{24}{7x-3}=\dfrac{-4}{25}\)
c) \(\dfrac{4}{x-6}=\dfrac{y}{24}=\dfrac{-12}{18}\)
d) \(\dfrac{-1}{5}\le\dfrac{x}{8}\le\dfrac{1}{4}\)
e) \(\dfrac{x+46}{20}=x\dfrac{2}{5}\)
f) \(y\dfrac{5}{y}=\dfrac{86}{y}\) ( \(x\dfrac{2}{5};y\dfrac{5}{y}\) là các hỗn số)
Tìm x:
\(\dfrac{x-3}{10}-\dfrac{x-3}{15}=\dfrac{x-3}{12}-\dfrac{x-3}{18}\)
Giúp mình với ạ!
1. tìm các số chưa biết :
a) \(\dfrac{4}{3}\)= \(\dfrac{8}{x}\)=\(\dfrac{-y}{21}\)=\(\dfrac{-40}{z}\)=\(\dfrac{16}{t}\)=\(\dfrac{y}{111}\)
b) \(\dfrac{-7}{6}=\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{14}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{4}{-78}\)
2. tìm x biết :
a) \(\dfrac{2}{x}=\dfrac{x}{8}\)
b) \(\dfrac{2x-9}{240}=\dfrac{39}{80}\)
c) \(\dfrac{x-1}{9}=\dfrac{8}{3}\)
mn giúp mk nha :>
tìm x:
\(\dfrac{x-}{7-}\dfrac{\dfrac{x}{12}+}{\dfrac{7}{12}}\dfrac{\dfrac{x}{18}}{\dfrac{7}{18}}=\dfrac{-4}{7}\)