Ta có: \(m_{giảm}=m_{O\left(oxit\right).tham.gia.phản.ứng}\)
=> \(n_O=\dfrac{8}{16}=0,5\left(mol\right)\)
PTHH:
\(Fe_3O_4+4H_2\xrightarrow[]{t^o}3Fe+4H_2O\\ ZnO+H_2\xrightarrow[]{t^o}Zn+H_2O\)
Theo PT: \(n_{H_2}=n_{O\left(oxit\right)}=0,5\left(mol\right)\)
=> VH2 = 0,5.22,4 = 11,2 (l)