\(\overrightarrow{AB}.\overrightarrow{AC}=AB.AC.cosA=2a.2a.cos60^0=2a^2\)
\(2\overrightarrow{AB}.3\overrightarrow{HC}=6\left(\overrightarrow{AH}+\overrightarrow{HB}\right).\overrightarrow{HC}=6\overrightarrow{AH}.\overrightarrow{HC}+6\overrightarrow{HB}.\overrightarrow{HC}\)
\(=6\overrightarrow{HB}.\overrightarrow{HC}=-6HC^2=-6a^2\)