Lời giải:
$\frac{1+14x}{5}=\frac{5-3x}{4}$
$\Rightarrow 4(1+14x)=5(5-3x)$
$4+56x=25-15x$
$56x+15x=25-4$
$71x=21$
$x=\frac{21}{71}$
c, \(\Rightarrow4+56x=25-15x\Leftrightarrow71x=21\Leftrightarrow x=\dfrac{21}{71}\)
\(\dfrac{1+14x}{5}=\dfrac{5-3x}{4}\)
\(\dfrac{4.\left(1+14x\right)}{20}=\dfrac{5.\left(5-3x\right)}{20}\)
\(4.\left(1+14x\right)=5.\left(5-3x\right)\)
\(4+56x=25-15x\)
\(56x+15x=25-4\)
\(71x=21\)
\(x=\dfrac{21}{71}\)
\(\Leftrightarrow\dfrac{4\left(1+14x\right)}{20}=\dfrac{5\left(5-3x\right)}{20}\)
\(\Leftrightarrow4\left(1+14x\right)=5\left(5-3x\right)\)
\(\Leftrightarrow4+56x=25-15x\)
\(\Leftrightarrow71x=21\Leftrightarrow x=\dfrac{21}{71}\)
