\(A=2x^2-6xy+9y^2-12x+2017\)
\(A=x^2+x^2-6xy+\left(3y\right)^2-12x+2014\)
\(A=\left(x^2-2\cdot x\cdot6+6^2\right)+\left[\left(3y\right)^2-2\cdot3y\cdot x+x^2\right]+1978\)
\(A=\left(x-6\right)^2+\left(3y-x\right)^2+1978\ge1978>0\forall x;y\)
P.s: 1978 năm sinh me t :)