Đặt \(\hept{\begin{cases}1\sqrt{x-1}=a\\\sqrt{y-1}=b\end{cases}}\)
Thì PT thành
a + a4 + 2a2 + 1 = b + b4 + 2b2 + 1
<=> (a - b) + (a - b)(a + b)(a2 + b2) + 2(a - b)(a +b) = 0
<=> (a - b)[1 + (a + b)(a2 + b2) + 2(a +b)] = 0
<=> a = b ( vì 1 + (a + b)(a2 + b2) + 2(a +b) > 0)
<=> \(1\sqrt{x-1}=\sqrt{y-1}\)
<=> x - 1 = y - 1
<=> x = y