\(n_{H_2}=a\left(mol\right)\)
\(2A+2nHCl\rightarrow2ACl_n+nH_2\)
\(2B+2mHCl\rightarrow2BCl_m+mH_2\)
\(n_{HCl}=2n_{H_2}=2a\left(mol\right)\)
\(BTKL:\)
\(10+2a\cdot36.5=11.42+2a\)
\(\Rightarrow a=0.02\)
\(V_{H_2}=0.02\cdot22.4=0.448\left(l\right)\)
Đúng 1
Bình luận (0)