a. Xét \(2\Delta\): \(\Delta AOC\) và \(\Delta BOC\) có:
\(\left\{{}\begin{matrix}OA=OC\left(gt\right)\\AC=BC\left(gt\right)\\OC.chung\end{matrix}\right.\)
\(\Rightarrow\Delta AOC=\Delta BOC\left(c.c.c\right)\)
b. Theo câu a, suy ra:
\(\widehat{OAC}=\widehat{OBC}\)
Mà: \(\widehat{OAC}=110^o\)
\(\Rightarrow\widehat{OBC}=110^o\)