\(A=2.sin\left(135^o\right)+cos\left(135^0\right)\\ =2.\dfrac{\sqrt{2}}{2}-\dfrac{\sqrt{2}}{2}\\ =\sqrt{2}-\dfrac{\sqrt{2}}{2}\\ =\dfrac{2\sqrt{2}-\sqrt{2}}{2}=\dfrac{\sqrt{2}}{2}\\ =>D\)
Thay `a=135^o` vào `A` có:
`A=2sin 135^o +cos 135^o`
`A=2. \sqrt{2}/2-\sqrt{2}/2`
`A=\sqrt{2}-\sqrt{2}/2`
`A=\sqrt{2}/2`
`->\bb D`