a:
Sửa đề: 4x^2/x^2-4
\(P=\dfrac{x^2-4x+4-x^2-4x-4+4x^2}{\left(x+2\right)\left(x-2\right)}\cdot\dfrac{-x\left(x-2\right)}{x+3}\)
\(=\dfrac{4x^2-8x}{\left(x+2\right)}\cdot\dfrac{-x}{x+3}=\dfrac{-4x^2\left(x-2\right)}{\left(x+2\right)\left(x+3\right)}\)
b: P=1
=>-4x^3+8x^2=x^2+5x+6
=>-4x^3+7x^2-5x-6=0
=>x=-0,58