\(a,b,c>0;a+b+c+2\sqrt{abc}=1\)
Để ý \(\sqrt{a\left(1-b\right)\left(1-c\right)}=\sqrt{a\left(1-b-c\right)+abc}=\sqrt{a\left(a+2\sqrt{abc}\right)+bc}=\sqrt{a^2+2a\sqrt{abc}+abc}=a+\sqrt{abc}\)
Khi đó \(P=a+b+c+3\sqrt{abc}-\sqrt{abc}+2024=1+2024=2025\)