Mg+Cl2-to>MgCl2
0,25---0,25----0,25 mol
n Mg=6\24=0,25 mol
m MgCl2=0,25.95=23,75g
VCl2=0,25.22,4=5,6l
a) PTHH : Mg + Cl2 -> MgCl2
\(n_{Mg}=\dfrac{m}{M}=\dfrac{6}{24}=0,25\left(mol\right)\)
b) \(m_{MgCl}=59,5.0,25=14,875\left(g\right)\)
c) \(V_{Cl}=0,25.22,4=5,6\left(l\right)\)
\(a,PTHH:Mg+Cl_2\underrightarrow{t^o}MgCl_2\)
\(b,n_{Mg}=\dfrac{m}{M}=\dfrac{6}{24}=0,25\left(mol\right)\\ Theo.PTHH:n_{Cl_2}=n_{MgCl_2}=n_{Mg}=0,25\left(mol\right)\\ m_{MgCl_2}=n.M=0,25.95=23,75\left(g\right)\\ c,V_{Cl_2\left(đktc\right)}=n.22,4=0,25.22,4=5,6\left(l\right)\)