\(n_{CO_2}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\)
\(V_{Ca\left(OH\right)_2}=100ml=0,1\left(l\right)\)
\(CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\)
\(CM_{Ca\left(OH\right)_2}=\dfrac{n}{V}=\dfrac{0,25}{0,1}=2,5M\)
\(m_{CaCO_3}=0,25.10025\left(g\right)\)