Câu 2:
V(C2H5OH)= 2 x 30/100= 0,6(l)
=> V(H2O)=V(H2O,C2H5OH) - V(C2H5OH)=2-0,6=1,4(l)
=> Cách pha: Rót thêm 1,4 lít nước vào 0,6 lít C2H5OH ta sẽ được 2 lít rượu etylic 30o
Câu 1 :
\(n_{CH_3COOH}=\dfrac{200\cdot12\%}{60}=0.4\left(mol\right)\)
\(2CH_3COOH+CaCO_3\rightarrow\left(CH_3COO\right)_2Ca+CO_2+H_2O\)
\(0.4........................0.2................0.2..................0.2\)
\(m_{CaCO_3}=0.2\cdot100=20\left(g\right)\)
\(V_{CO_2}=0.2\cdot22.4=4.48\left(l\right)\)
\(m_{\left(CH_3COO\right)_2Ca}=0.2\cdot158=31.6\left(g\right)\)
Câu 1:
mCH3COOH=200.12%=24(g) -> nCH3COOH=0,4(mol)
PTHH: 2 CH3COOH + CaCO3 -> (CH3COO)2Ca + H2O + CO2
0,4_______________0,2_________0,2__________________0,2(mol)
=> V(CO2,đktc)=0,2.22,4=4,48(l)
a=mCaCO3=0,2.100=20(g)