b: Tọa độ giao điểm là:
\(\left\{{}\begin{matrix}x^2+x-2=0\\y=x^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left(x+2\right)\left(x-1\right)=0\\y=x^2\end{matrix}\right.\)
=>A(-2;4); B(1;1)
\(AB=\sqrt{\left(-1-2\right)^2+\left(1-4\right)^2}=3\sqrt{2}\)
c: Vì y=2x nên \(2x=x^2\)
\(\Leftrightarrow x=2\left(x< >0\right)\)
Vậy: C(2;4)