Question

Biết rằng: \(\dfrac{x+3y}{x-2y}=\dfrac{4}{3},\left(x-2y\ne0\right)\). Khi đó \(\dfrac{x}{y}\left(y\ne0\right)\) bằng:

Answer 1

\(\Leftrightarrow3x+9y=4x-8y\)

\(\Leftrightarrow x=17y\)

hay \(\dfrac{x}{y}=\dfrac{17}{1}\)

Answer 2

\(\Leftrightarrow3\left(x+3y\right)=4\left(x-2y\right)\\ \Leftrightarrow3x+9y=4x-8y\\ \Leftrightarrow x=17y\Leftrightarrow\dfrac{x}{y}=17\)