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Bài 1 : Tính
1) ( 5^29 × 5^40) : 5^67 (Là : (5 ngũ 29 × 5 ngũ 40) : 5 ngũ 67
2) (2^2 × 2^3 × 2^4) : 2^5
3) (4^4 × 4^6 × 4^12 ) : 4^15
4) (7^7 × 7 × 7^15) : 7^20
5) (3^3 × 3^6 × 3) : 3^10
6) (6^6 × 6 × 6^12 ) : 6^7
7) (5^2 × 5^5 ) : (5× 5^6)
8) (8^10 × 8^8) : (8^8 : 8^4 )
9) (2^20 × 2^21 ) : ( 2^10 × 2^11)
Bài 2 : Tìm x biết
1) 3^x = 3^4 (Là 3 ngũ x = 3 ngũ 4
2) 2^x = 2^9
3) 6^x = 6^10
4) 5^x = 5^2
5) 2^x = 16
6) 5^x = 25
7) 3^x = 27
8) 9^x = 81
9) 4^x = 64
10) 8^x = 64
11) 7^x = 49
12) 11^x = 121
Bài 2: Tìm x biết
1) 4^x = 4^3 × 4^5
2) 7^x = 7 × 7^7
3) 5^x = 5^3 × 5^5
4) 8^x = 8^3 × 8^5
5) 5^x = 5^15 : 5^3
6) 9^x = 9^20 : 9^5
7) 4^x = 4^15 : 4^5
8) 7^x = 7^20 : 7^10
Dài thế này thì ế lắm khó trả lời được 😅
Bài 2:
`1)4^x=4^3*4^5`
`=>4^x=4^8`
`=>x=8`
`2)7^x=7*7^7`
`=>7^x=7^8`
`=>x=8`
`3)5^x=5^3*5^5`
`=>5^x=5^8`
`=>x=8`
`4)8^x=8^3*8^5`
`=>8^x=8^8`
`=>x=8`
`5)5^x=5^15:5^3`
`=>5^x=5^12`
`=>x=12`
`6)9^x=9^20:9^5`
`=>9^x=9^15`
`=>x=15`
`7)4^x=4^15:4^5`
`=>4^x=4^10`
`=>x=10`
`8)7^x=7^20:7^10`
`=>7^x=7^10`
`=>x=10`
Bài 1:
1: \(\dfrac{5^{29}\cdot5^{40}}{5^{67}}=\dfrac{5^{29+40}}{5^{67}}=\dfrac{5^{69}}{5^{67}}=5^2=25\)
2: \(\dfrac{2^2\cdot2^3\cdot2^4}{2^5}=\dfrac{2^{2+3}}{2^5}\cdot2^4=2^4\)
3: \(\dfrac{4^4\cdot4^6\cdot4^{12}}{4^{15}}=\dfrac{4^{4+6+12}}{4^{15}}=\dfrac{4^{22}}{4^{15}}=4^7\)
4: \(\dfrac{7^7\cdot7\cdot7^{15}}{7^{20}}=\dfrac{7^{7+1+15}}{7^{20}}=\dfrac{7^{23}}{7^{20}}=7^3\)
5: \(\dfrac{3^3\cdot3^6\cdot3}{3^{10}}=\dfrac{3^{3+6+1}}{3^{10}}=\dfrac{3^{10}}{3^{10}}=1\)
6: \(\dfrac{6^6\cdot6\cdot6^{12}}{6^7}=6^7\cdot\dfrac{6^{12}}{6^7}=6^{12}\)
7: \(\dfrac{5^2\cdot5^5}{5\cdot5^6}=\dfrac{5^7}{5^7}=1\)
8: \(\dfrac{8^{10}\cdot8^8}{8^8:8^4}=\dfrac{8^{18}}{8^4}=8^{14}\)
9: \(\dfrac{2^{20}\cdot2^{21}}{2^{10}\cdot2^{11}}=\dfrac{2^{20+21}}{2^{10+11}}=\dfrac{2^{41}}{2^{21}}=2^{20}\)
