Question

Bài này làm như nào nhỉ?

Answer 1

\(a,=\left(2x-1\right)^2\\ b,=2\left(8y^3-x^3-3x^2-3x-1\right)\\ =2\left[8y^3-\left(x+1\right)^3\right]\\ =2\left(2y-x-1\right)\left[4y^2+2y\left(x+1\right)+\left(x+1\right)^2\right]\\ =2\left(2y-x-1\right)\left(4y^2+2xy+2y+x^2+2x+1\right)\\ c,=2x^2+2x+5x+5=\left(x+1\right)\left(2x+5\right)\\ d,=\left(x-3y\right)^2-25z^2=\left(x-3y-5z\right)\left(x-3y+5z\right)\)

Answer 2

a) 4x²-4x+1

= (2x-1)²

b)16y³-2x³-6x(x+1)-2

= −2x³+16y³−6x²−6x−2

= 2(−x³+8y³−3x²−3x−1)