a) Ta có: \(\dfrac{-51}{100}=-0,51\)
Vì \(0,51>0,5\) nên \(-0,51< -0,5\)
hay \(-0,5>\dfrac{-51}{100}\)
b) Ta có: \(1\dfrac{7}{9}=\dfrac{16}{9}=\dfrac{80}{45}\); \(\dfrac{9}{5}=\dfrac{81}{45}\)
Vì \(80< 81\) nên \(\dfrac{80}{45}< \dfrac{81}{45}\)
hay \(1\dfrac{7}{9}< \dfrac{9}{5}\)
c) Có: \(\dfrac{-295}{118}-1=\dfrac{-295-118}{118}=\dfrac{-413}{118}\)
Lại có: \(\dfrac{-280}{133}-1=\dfrac{-280-133}{133}=\dfrac{-413}{133}\)
Vì \(118< 133\) nên \(\dfrac{1}{118}>\dfrac{1}{133}\)
\(\Rightarrow\dfrac{-413}{118}< \dfrac{-413}{133}\Rightarrow\dfrac{-295}{118}-1< \dfrac{-280}{133}-1\)
hay \(\dfrac{-295}{118}< \dfrac{-280}{133}\)
d) Ta có: \(-\dfrac{15}{37}< -\dfrac{15}{39}=-\dfrac{5}{13}=\dfrac{10}{-26}< \dfrac{10}{-29}\)
#$\mathtt{Toru}$