Question

Bài 1: tính

k)\(\left(\dfrac{10}{3}+\dfrac{5}{2}\right)\):\(\left(\dfrac{19}{6}-\dfrac{21}{5}\right)\)-\(\dfrac{11}{31}\)

_{Cần gấp ạ}

 

 

Answer 1

\(\left(\dfrac{10}{3}+\dfrac{5}{2}\right):\left(\dfrac{19}{6}-\dfrac{21}{5}\right)-\dfrac{11}{31}\)

\(=\left(\dfrac{20}{6}+\dfrac{15}{6}\right):\left(\dfrac{95}{30}-\dfrac{126}{30}\right)-\dfrac{11}{31}\)

\(=\dfrac{35}{6}\cdot\dfrac{30}{-31}-\dfrac{11}{31}=\dfrac{-35\cdot5-11}{31}=\dfrac{-186}{31}=-6\)

Answer 2

`=(10/3 + 5/2) : (19/6 - 21/5) - 11/31`

`=(20/6 + 15/6) :(95/30 - 126/30) - 11/31`

`=35/6 : (-31/30) - 11/31`

`=35/6 . (-30/31) - 11/31`

`=-175/31 - 11/31`

`=-6`

Answer 3

k)\(\left(\dfrac{10}{3}+\dfrac{5}{2}\right):\left(\dfrac{19}{6}-\dfrac{21}{5}\right)-\dfrac{11}{31}\)

\(=\dfrac{35}{6}:-\dfrac{31}{30}-\dfrac{11}{31}\)

\(=\dfrac{35}{6}\cdot-\dfrac{30}{31}-\dfrac{11}{31}\)

\(=-\dfrac{175}{31}-\dfrac{11}{31}=-\dfrac{186}{31}=-6\)