24 tháng 2 2022 lúc 11:03
Các câu hỏi tương tự
Bài 1. Tính A left(8dfrac{2}{7}-4dfrac{2}{7}right)-3dfrac{4}{9} B left(10dfrac{2}{9}-6dfrac{2}{9}right)+2dfrac{3}{5}Bài 2. Tính a) 5dfrac{1}{2}.3dfrac{1}{4} b) 6dfrac{1}{3}:4dfrac{2}{9} c) 4dfrac{3}{7}.2
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Bài 1. Tính
A= \(\left(8\dfrac{2}{7}-4\dfrac{2}{7}\right)-3\dfrac{4}{9}\)
B= \(\left(10\dfrac{2}{9}-6\dfrac{2}{9}\right)+2\dfrac{3}{5}\)
Bài 2. Tính
a) \(5\dfrac{1}{2}.3\dfrac{1}{4}\) b) \(6\dfrac{1}{3}:4\dfrac{2}{9}\) c) \(4\dfrac{3}{7}.2\)
Bài 1: Thực hiện phép tínha) 1-dfrac{1}{2}+dfrac{1}{3}b) dfrac{2}{5}+dfrac{3}{5}:dfrac{9}{10}c) dfrac{7}{11}.dfrac{3}{4}+dfrac{7}{11}.dfrac{1}{4}+dfrac{4}{11}d) left(dfrac{3}{4}+0,5+25%right).2dfrac{2}{3}Bài 2:text{Tìm x}a) x+dfrac{1}{2}2b) 75%x-dfrac{1}{2}-1dfrac{1}{4}c) left|x-dfrac{2}{5}right|+dfrac{7}{10}3
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Bài 1: Thực hiện phép tính
a) \(1-\dfrac{1}{2}+\dfrac{1}{3}\)
b) \(\dfrac{2}{5}+\dfrac{3}{5}:\dfrac{9}{10}\)
c) \(\dfrac{7}{11}.\dfrac{3}{4}+\dfrac{7}{11}.\dfrac{1}{4}+\dfrac{4}{11}\)
d) \(\left(\dfrac{3}{4}+0,5+25\%\right).2\dfrac{2}{3}\)
\(Bài 2:\text{Tìm x}\)
a) \(x+\dfrac{1}{2}=2\)
b) \(75\%x-\dfrac{1}{2}=-1\dfrac{1}{4}\)
c) \(\left|x-\dfrac{2}{5}\right|+\dfrac{7}{10}=3\)
11 tháng 4 2021 lúc 15:06
text{Bài 4. Chứng tỏ rằng:}a) dfrac{1}{2^2}+dfrac{1}{3^2}+dfrac{1}{4^2}+...+dfrac{1}{30^2} 1b) dfrac{1}{10}+dfrac{1}{11}+dfrac{1}{12}+...+dfrac{1}{99}+dfrac{1}{100}1c) dfrac{1}{5}+dfrac{1}{6}+dfrac{1}{7}+...+dfrac{1}{17} 2d) dfrac{1}{1.2}+dfrac{1}{2.3}+dfrac{1}{3.4}+...+dfrac{1}{29.30} 1
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\(\text{Bài 4. Chứng tỏ rằng:}\)
\(a\)) \(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{30^2}< 1\)
\(b\)) \(\dfrac{1}{10}+\dfrac{1}{11}+\dfrac{1}{12}+...+\dfrac{1}{99}+\dfrac{1}{100}>1\)
\(c\)) \(\dfrac{1}{5}+\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{17}< 2\)
\(d\)) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{29.30}< 1\)
Cho: \(\dfrac{a}{(b)^{2}} = \dfrac{b^{2}}{(c)^{3}} = \dfrac{c^{3}}{(a)^{4}}\)
Tính P =\((1 + \dfrac{a}{b}).(1+\dfrac{b}{c}).(1+\dfrac{c}{a})\)
Giúp mk với mk đg cần gấp
a) x + dfrac{2}{5} dfrac{1}{2}b) x - dfrac{2}{5} dfrac{2}{7}c) dfrac{3}{5} - x dfrac{1}{10}d) x . dfrac{3}{4} dfrac{9}{20}e) x : dfrac{1}{7} 14f) ( dfrac{1}{4} + x ) . dfrac{1}{2} dfrac{2}{5}g) x . dfrac{2}{3} - dfrac{2}{3} dfrac{9}{12}h) dfrac{3}{4} + dfrac{1}{4} : x dfrac{2}{5}k) 3dfrac{4}{5} - x dfrac{18}{5}l) x . 2dfrac{1}{3} dfrac{3}{4}m) x . dfrac{6}{11} + x . dfrac{5}{11} 2025n) x . dfrac{14}{9} - x . dfrac{7}{9} + x . dfrac{5}{9} 2Các bạn làm theo cách bình thường ở lớp...
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a) x + \(\dfrac{2}{5}\) = \(\dfrac{1}{2}\)
b) x - \(\dfrac{2}{5}\) = \(\dfrac{2}{7}\)
c) \(\dfrac{3}{5}\) - x = \(\dfrac{1}{10}\)
d) x . \(\dfrac{3}{4}\) = \(\dfrac{9}{20}\)
e) x : \(\dfrac{1}{7}\) = 14
f) ( \(\dfrac{1}{4}\) + x ) . \(\dfrac{1}{2}\) = \(\dfrac{2}{5}\)
g) x . \(\dfrac{2}{3}\) - \(\dfrac{2}{3}\) = \(\dfrac{9}{12}\)
h) \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) : x = \(\dfrac{2}{5}\)
k) \(3\dfrac{4}{5}\) - x = \(\dfrac{18}{5}\)
l) x . \(2\dfrac{1}{3}\) = \(\dfrac{3}{4}\)
m) x . \(\dfrac{6}{11}\) + x . \(\dfrac{5}{11}\) = 2025
n) x . \(\dfrac{14}{9}\) - x . \(\dfrac{7}{9}\) + x . \(\dfrac{5}{9}\) = 2
Các bạn làm theo cách bình thường ở lớp 5 cho mính nhé!
Chú ý: dấu "." là dấu nhân.
Tính: a) dfrac{13}{14}-dfrac{-7}{8}+dfrac{-3}{2}b) dfrac{5}{17}+dfrac{-15}{34}.dfrac{2}{5}c) dfrac{1}{5}:dfrac{1}{10}-dfrac{1}{3}.(dfrac{6}{5}-dfrac{2}{4})d) dfrac{-3}{4}:(dfrac{12}{-5}-dfrac{-7}{10})*Lưu ý: Không viết luôn kết quả, giải chi tiết.
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Tính:
a) \(\dfrac{13}{14}\)-\(\dfrac{-7}{8}\)+\(\dfrac{-3}{2}\)
b) \(\dfrac{5}{17}\)+\(\dfrac{-15}{34}\).\(\dfrac{2}{5}\)
c) \(\dfrac{1}{5}\):\(\dfrac{1}{10}\)-\(\dfrac{1}{3}\).(\(\dfrac{6}{5}\)-\(\dfrac{2}{4}\))
d) \(\dfrac{-3}{4}\):(\(\dfrac{12}{-5}\)-\(\dfrac{-7}{10}\))
*Lưu ý: Không viết luôn kết quả, giải chi tiết.
3. Tính :a/ dfrac{-1}{2} + dfrac{5}{6} + dfrac{1}{3} b/ dfrac{-3}{8} + dfrac{7}{4} - dfrac{1}{12} c/ dfrac{3}{5} : (dfrac{1}{4} . dfrac{7}{5}) d/ dfrac{10}{11} + dfrac{4}{11} : 4 - dfrac{1}{8}
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3. Tính :
a/ \(\dfrac{-1}{2}\) + \(\dfrac{5}{6}\) + \(\dfrac{1}{3}\) b/ \(\dfrac{-3}{8}\) + \(\dfrac{7}{4}\) - \(\dfrac{1}{12}\) c/ \(\dfrac{3}{5}\) : (\(\dfrac{1}{4}\) . \(\dfrac{7}{5}\)) d/ \(\dfrac{10}{11}\) + \(\dfrac{4}{11}\) : 4 - \(\dfrac{1}{8}\)
B=\(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{7}{6}}{2\dfrac{2}{5}}\)
Tính B.
Mn giúp tớ vs
Bài 1.(2,5 điểm)Tìm x, biết:a) left(2dfrac{1}{3}+3dfrac{1}{2}right).x-4dfrac{1}{6}+3dfrac{1}{2}b) left(1dfrac{1}{3}+3dfrac{1}{2}right).x4dfrac{1}{6}-3dfrac{1}{2}c) dfrac{1}{3}-dfrac{7}{8}.xdfrac{1}{4}d) dfrac{3}{2}.x+dfrac{1}{7}dfrac{7}{8}.dfrac{64}{49}e) 5dfrac{1}{2}-left(dfrac{1}{4}.x+dfrac{2}{5}right)25%
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Bài 1.(2,5 điểm)Tìm x, biết:
a) \(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right).x=-4\dfrac{1}{6}+3\dfrac{1}{2}\)
b) \(\left(1\dfrac{1}{3}+3\dfrac{1}{2}\right).x=4\dfrac{1}{6}-3\dfrac{1}{2}\)
c) \(\dfrac{1}{3}-\dfrac{7}{8}.x=\dfrac{1}{4}\)
d) \(\dfrac{3}{2}.x+\dfrac{1}{7}=\dfrac{7}{8}.\dfrac{64}{49}\)
e) \(5\dfrac{1}{2}-\left(\dfrac{1}{4}.x+\dfrac{2}{5}\right)=25\%\)