Bài 1 :
Đề bài khó nhìn quá .
Bài 2 :
a ) ( a + b )3 + ( a - b )3
= ( a + b + a - b ) [ ( a + b )2 - ( a + b ) ( a - b ) + ( a - b )2 ]
= 2a ( a2 + 2ab + b2 - a2 + b2 + a2 - 2ab + b2 )
= 2a ( a2 + 2b2 ) = 2a3 + 4ab2
b ) ( a + b )3 - ( a - b )3
= ( a + b - a + b ) [ ( a + b )2 + ( a + b ) ( a - b ) + ( a - b )2 ]
= 2b ( a2 + 2ab + b2 + a2 - b2 + a2 - 2ab + b2 )
= 2b ( 3a2 + b2 ) = 6a2b + 2b3